Question
Download Solution PDFComprehension
Direction: Study the given information and answer the following questions:
Eight persons namely A, B, C, E, F, G, H, and K are buying groceries but not necessarily in the same order. Only two persons buy before A. G buys immediately after F. Only one person buys after E. The number of persons who bought groceries between A and G is two. K buys immediately before F. The number of persons who bought between H and C is zero with C buying after H.
Which of the following is the odd pair out?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven: Eight persons namely A, B, C, E, F, G, H, and K are buying groceries but not necessarily in the same order.
Based on the conditions given, we get the following possibilities:
1. Only two persons buy before A.
The number of persons who bought groceries between A and G is two.
Combining these, we get-
S.No. |
PERSONS |
1. |
|
2. |
|
3. |
A |
4. |
|
5. |
|
6. |
G |
7. |
|
8. |
|
2. G buys immediately after F.
K buys immediately before F.
Combining these, we get-
S.No. |
PERSONS |
1. |
|
2. |
|
3. |
A |
4. |
K |
5. |
F |
6. |
G |
7. |
|
8. |
|
3. The number of persons who bought between H and C is zero with C buying after H.
Only one person buys after E.
Combining these, we get the final arrangement as follows:
S.No. |
PERSONS |
1. |
H |
2. |
C |
3. |
A |
4. |
K |
5. |
F |
6. |
G |
7. |
E |
8. |
B |
Therefore, we see that apart from CE, all the other given pairs have two persons between them.
Hence, CE is the odd one out.
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