Which of the following displacement diagram is chosen for better dynamic performance of a cam follower mechanism? 

This question was previously asked in
JKSSB JE ME 2015 Official Paper
View all JKSSB JE Papers >
  1. Simple Harmonic motion
  2. Parabolic motion
  3. Cycloidal motion
  4. Hyperbolic motion

Answer (Detailed Solution Below)

Option 3 : Cycloidal motion
Free
JKSSB JE Civil RCC Structures Mock Test
1.2 K Users
20 Questions 20 Marks 20 Mins

Detailed Solution

Download Solution PDF

Explanation:

Cycloidal motion: 

  • cycloidal motion curve has the best dynamic characteristics.
  • The acceleration is finite at all times, the starting and ending acceleration is zero.
  • It will yield a cam mechanism with the lowest vibration, stress, noise and shock characteristics. Hence for the high-speed engine, the cam follower should move with Cycloidal motion.

326

Additional Information

Simple Harmonic Motion: Since the follower moves with a simple harmonic motion, therefore velocity diagram consists of a sine curve and the acceleration diagram is a cosine curve.

  • velocity of the follower is zero at the beginning and at the end of its stroke and increases gradually to a maximum at mid-stroke.
  • acceleration of the follower is maximum at the beginning and at the ends of the stroke and diminishes to zero at mid-stroke

325

Uniform Acceleration and Retardation: The round corners of the displacement diagram are usually parabolic curves because the parabolic motion results in a very low acceleration of the follower for a given stroke and cam speed

TOM 12

Uniform velocity motion:

324

Latest JKSSB JE Updates

Last updated on Jul 1, 2025

-> JKSSB Junior Engineer recruitment exam date 2025 for Civil and Electrical Engineering has been rescheduled on its official website. 

-> JKSSB JE exam will be conducted on 31st August (Civil), and on 24th August 2025 (Electrical).

-> JKSSB JE application form correction facility has been started. Candidates can make corrections in the JKSSB recruitment 2025 form from June 23 to 27. 

-> JKSSB JE recruitment 2025 notification has been released for Civil Engineering. 

-> A total of 508 vacancies has been announced for JKSSB JE Civil Engineering recruitment 2025. 

-> JKSSB JE Online Application form will be activated from 18th May 2025 to 16th June 2025 

-> Candidates who are preparing for the exam can access the JKSSB JE syllabus PDF from official website of JKSSB.

-> The candidates can check the JKSSB JE Previous Year Papers to understand the difficulty level of the exam.

-> Candidates also attempt the JKSSB JE Mock Test which gives you an experience of the actual exam.

Get Free Access Now
Hot Links: teen patti - 3patti cards game teen patti bodhi teen patti rules teen patti gold apk