Question
Download Solution PDFWhen two monochromatic lights of frequency, v and
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCONCEPT:
- When the photons fall on a metal surface then some electrons get ejected from the metal surface.This phenomenon is called the photoelectric effect.
- The minimum energy needed to remove electrons from the metal surface is called work function (φ) of that metal.
- The maximum energy of ejected electrons from the metal surface after ejection is called as maximum kinetic energy (KEmax).
- Einstein’s equation of photoelectric equation:
Where ν = frequency of incident energy of photons, νo = threshold frequency, and KE = the maximum kinetic energy of electrons.
Here Wo = hνo
If Vo is the stopping potential, e is the electronic charge, then
KEmax = eVo
⇒ eVo = (hν - hνo)
⇒ hν = hνo + eVo
Calculation:
Frequency of first monochromatic light, ν1 = ν
Stopping the potential of the first monochromatic light, V1 =
We know,
Then, hν = W + eV1
⇒
Frequency of second monochromatic light, ν2 = ν/2
Stopping potential second monochromatic light, V2 = Vs
Then,
Equate the value of W,
⇒ Vs = - h ν/e
Put this equation 1,
W = 1.5 hν
hν0 = 1.5 hν
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