Question
Download Solution PDFWhen 0.1 m3/s water flows through a pipe of area 0.25 m2, which later reduces to 0.1 m2, what is the velocity of flow in the reduced pipe?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Continuity equation: It is the conservation of mass flow rate.
- ρ1A1V1 = ρ1A1V1
For incompressible fluid density will be constant thus continuity equation will be:
- A1V1 = A2V2
where, A1, A2 = area of section 1 & 2 respectively, V1, V2 = velocity of section 1 & 2 respectively
The flow rate of liquid is equal to Q = AV.
Calculation:
Given:
Area: A1 = 0.25 m2, A2 = 0.1 m2.
Flow rate: Q = 0.1 m3/s.
Q = A1V1 = A2V2
\(V_1 = \frac{Q}{A_1} = \frac{0.1}{0.25} = 0.4\ m/s\)
\(V_2 = \frac{Q}{A_2} = \frac{0.1}{0.1} = 1\ m/s\)
∴ The velocity of flow in the reduced pipe is 1 m/s
Last updated on May 28, 2025
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