What is the value of x that satisfies 4 cos2 30° + 2x sin 30° - cot2 30° - 6 tan 15° tan 75° = 0 ? 

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CDS Elementary Mathematics 16 April 2023 Official Paper
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  2. 2
  3. 3
  4. 6

Answer (Detailed Solution Below)

Option 4 : 6
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Detailed Solution

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Formula used:

cos(30°) = √3/2

sin(30°) = 1/2

cot(30°) = √3

tan (90° - θ) = cot θ 

tan θ × cot θ = 1

Calculation:

4 cos2 30° + 2x sin 30° - cot2 30° - 6 tan 15° tan 75° = 0

Since, tan (90° - θ) = cot θ 

⇒ 4 cos2 30° + 2x sin 30° - cot2 30° - 6 tan (90° - 75°) tan 75° = 0

⇒ 4 cos2 30° + 2x sin 30° - cot2 30° - 6 cot 75° tan 75° = 0

But, tan θ × cot θ = 1

⇒ 4 cos2 30° + 2x sin 30° - cot2 30° - 6 = 0

Using the trigonometric values

⇒ 4(√3/2)2 + 2x(1/2) - (√3)- 6= 0

⇒ 3 + x - 3 - 6 = 0

∴ x = 6

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