What is the total capacitance in the given circuit?

Concept:

When capacitors are connected in parallel, the total capacitance is the sum of the individual capacitors' capacitances.

\(C_{{eq}}(parallel) = {C_1} + {C_2} + {C_3} + \ldots + {C_4}\)

When capacitors are connected in series, the total capacitance is less than the least capacitance connected in series.

\(\frac{1}{{{C_{eq}(series)}}} = \frac{1}{{{C_1}}} + \frac{1}{{{C_2}}} + \ldots + \frac{1}{{{C_n}}}\)

Calculation:

For the two 6 F capacitors connected in parallel, the resultant capacitance will be:

C_net = 6 + 6 = 12 F

Also, the two 2F capacitors connected in series connection will be equivalent to a single capacitor of value:

C_net = 2/2 = 1 F

The resultant circuit is drawn as:

Since the 1 F and 12 F capacitors are connected in parallel, the net capacitance will be:

C_net = 1 + 12 = 13 F