What is the least number that should be added to 1056 so that the sum is completely divisible by 23 ?

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CSIR CERI JSA Official Paper-I (Held On: 2022)
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  1. 2
  2. 3
  3. 18
  4. 21

Answer (Detailed Solution Below)

Option 1 : 2
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Detailed Solution

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Given:

Number to be added to 1056 so that the sum is completely divisible by 23.

Calculation:

First, find the remainder when 1056 is divided by 23.

⇒ Remainder = 1056 - (23 × (1056 ÷ 23))

⇒ Remainder = 1056 - (23 × 45)

⇒ Remainder = 1056 - 1035

⇒ Remainder = 21

Number that should be added = 23 - 21 = 2

Therefore, we need to add 2 to 1056 to make it completely divisible by 23.

∴ The correct answer is option 1.

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