What is the functionality of the program given below?

MOV A, #0

MOV R2, #10

AGAIN: ADD A, #03

DJNZ R2, AGAIN

MOV R5, A

Question

Question

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BSPHCL JE Electrical 2019 Official Paper: Batch 2 (Held on 30 Jan 2019)

It clears the accumulator and then add value 3 to the accumulator 10 times
It adds the content of R2 and A and then store the result in accumulator
It decrements the register R2 10 times and then store value 3 to the accumulator
It clears the accumulator and then add value 13 to the accumulator 10 times

Answer 1

It clears the accumulator and then adds the value 3 to the accumulator 10 times.
Explanation:

The instruction MOV A, #0 clears the accumulator A by moving the value 0 into it.
The instruction MOV R2, #10 moves the value 10 into register R2.
The program enters a loop labeled "AGAIN."
Within the loop, the instruction ADD A, #03 adds the value 3 to the accumulator A.
The instruction DJNZ R2, AGAIN decrements the value of register R2 by 1 and jumps back to the label "AGAIN" if the result is not zero. This loop is executed 10 times since the initial value of R2 is 10.
After the loop completes, the instruction MOV R5, A moves the value in the accumulator A to register R5.
Therefore, the correct answer is:
It clears the accumulator and then adds the value 3 to the accumulator 10 times.