What is the curl of the vector field 2x2yi + 5z2j - 4yzk?

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GATE CE 2019 Official Paper: Shift 2
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  1. 14zi2x2k
  2. 6zi+4xj2x2k
  3. 6zi+8xy+2x2yk
  4. 14zi+6yj+2x2k

Answer (Detailed Solution Below)

Option 1 : 14zi2x2k
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Detailed Solution

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Concept:

Consider the vector field

V=2x2yi+5z2j4yzk

curlV=×V=|ijkxyz2x2y5z24yz|

CurlV=i[y(4yz)z(5z2)]j[x(4yz)z(2x2y)]+k[x(5z2)y(2x2y)]

CurlV=i[4z10z]j[0]+k[2x2]

CurlV=14zi2x2k
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