What is the angle between the planes 2x - y - 2z + 1 = 0 and 3x - 4y + 5z - 3 = 0 ?

  1. π / 6
  2. π / 4
  3. π / 3
  4. π / 2

Answer (Detailed Solution Below)

Option 4 : π / 2
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Detailed Solution

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Concept:

Let a1x + b1y + c1z + d= 0 and a2x + b2y + c2z + d2 = 0 be any two planes . then the angle between them is given by ,

Calculations :

Given the planes are  2x - y - 2z + 1 = 0 and 3x - 4y + 5z - 3 = 0 .

We know that , a1x + b1y + c1z + d= 0 and a2x + b2y + c2z + d2 = 0 be any two planes . then the angle between them is given by ,

Here , a= 2, a= 3, b= - 1, b= - 4, c= - 2, c= 5.

⇒ 

Hence, the angle between the planes 2x - y - 2z + 1 = 0 and 3x - 4y + 5z - 3 = 0 is 

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