Water has a critical specific volume of 0.003155 m³/kg. A closed and rigid steel tank of volume 0.025 m³ contains a mixture of water and steam at 0.1 MPa. The mass of the mixture is 10 kg. The tank is now slowly heated. The liquid level inside the tank

Explanation:

In the question, critical specific volume V_c = 0.003155 m³/kg is given.

Mixture specific volume v = \(\frac{{0.025\;}}{{10}}\) = 0.0025 m³/kg.

As V < V_c and due to the water mixture's heating temperature will rise and hence pressure will rise.

As pressure rises, the mixture's state will change from 1 to 2 as the rigid tank is given in the question so the mixture's total volume will be constant.

At state 1 quality is X₁ and at state 2 quality of the mixture will be X₂.

From figure X₂ < X₁. It means the liquid at state 2 will be more. Since liquid at state 2 is more therefore level of liquid inside the tank will rise.