Three taps A, B and C together can fill an empty cistern in 11 minutes. Tap A alone can fill it in 66 minutes and tap B can fill it in 33/2 minutes. How much time will tap C alone take to fill it?

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  1. 66 minutes
  2. 60 minutes
  3. 40 minutes
  4. 55 minutes

Answer (Detailed Solution Below)

Option 1 : 66 minutes
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Detailed Solution

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Given:

A, B, and C together fill the cistern in 11 minutes.

A alone fills the cistern in 66 minutes.

B alone fills the cistern in 33/2 minutes.

Calculations:

Let the total capacity of the cistern be the LCM of 11, 66, and 33/2 = 66.

Efficiency of A, B, and C together = 66 / 11 = 6 units/minute

Efficiency of A = 66 / 66 = 1 unit/minute

Efficiency of B = 66 / (33/2) = 66 × (2/33) = 4 units/minute

Efficiency of C = (Efficiency of A, B, and C together) - (Efficiency of A) - (Efficiency of B)

Efficiency of C = 6 - 1 - 4 = 1 unit/minute

Time taken by C alone to fill the cistern = Total capacity / Efficiency of C

Time taken by C = 66 / 1 = 66 minutes

∴ Tap C alone will take 66 minutes to fill the cistern.

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