Three candidates solve a question. Odds in favour of the correct answer are 5 : 2, 4 : 3 and 3 : 4 respectively for the three candidates. What is the probability that at least two of them solve the question correctly?

This question was previously asked in
NDA (Held On: 18 Sept 2016) Maths Previous Year paper
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  1. 209/343
  2. 134/343
  3. 149/343
  4. 60/343

Answer (Detailed Solution Below)

Option 1 : 209/343
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Detailed Solution

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Concept:

Let an event A, Probability of occurring of A be P (A) and not occurring of A be P (Ac)


Calculation:

Let A, B, C be the three students.

Let P(A), P(B), P(C) be the probabilities that students A,B and C answer the question correctly.

We know that,

 Odds in favour of A       …. (1)

(Odds in favour of A)+1      …. (2)

Equation 1 divide by 2, we get

Similarly, 

Probability that at least two candidates solve correctly,

P(E) = P(A)P(B)P(Cc) + P(A)P(Bc)P(C) + P(Ac)P(B)P(C) + P(A)P(B)P(C)

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