Three bells make a beeping sound after every 48 seconds, 72 seconds 108 seconds respectively. They beeped together at 10 AM. The time (hh:mm:ss), when they will next beep together at the earliest is:

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  1. 10 : 07 : 48
  2. 10 : 07 : 12
  3. 10 : 07 : 24
  4. 10 : 07 : 36

Answer (Detailed Solution Below)

Option 2 : 10 : 07 : 12
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Detailed Solution

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Given:

Bells beep every 48 seconds, 72 seconds, and 108 seconds respectively.

They beeped together at 10 AM.

Formula Used:

Time when they will beep together again = LCM(48, 72, 108)

Calculation:

Prime factorization of 48: 24 × 3

Prime factorization of 72: 23 × 32

Prime factorization of 108: 22 × 33

LCM = 24 × 33

LCM = 16 × 27

LCM = 432 seconds

432 seconds = 432 / 60 = 7 minutes 12 seconds

10:00:00 + 00:07:12 = 10:07:12

The time when they will next beep together at the earliest is 10:07:12.

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