There are 15 terms in an arithmetic progression. Its first term is 5 and their sum is 390. Find the middle term.

  1. 23
  2. 26
  3. 28
  4. 32

Answer (Detailed Solution Below)

Option 2 : 26
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Here, n = 15; a = 5 and Sum = 390

Applying the sum formula to find the common difference,

\(390 = \frac{{15}}{2}\left[ {2 \times 5 + 14d} \right] = 15 \times \left( {5 + 7d} \right)\)

⇒ 5 + 7d = 26

⇒ d = 3

∴ The middle term = 8th term = a + 7d = 5 + 21 = 26

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