The velocity field in a flow system is given by v=2i+(x+y)j+(xyz)k. The acceleration of the fluid at (1, 1, 2) is

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  1. j + k
  2. 2i + 10 k
  3. 4j + 10 k
  4. 4i + 12 k

Answer (Detailed Solution Below)

Option 3 : 4j + 10 k
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Velocity field (v)=2i+(x+y)j+(xyz)k

Acceleration(an)=(δvδt)+(uδvδx+vδvδy+w(δv)δz)

Where (δvδt)Localaccelaration

(uδvδx+vδvδy+w(δv)δz)Convectiveaccelaration

Here, u=2,v=x+y,w=xyz,t=0, n is direction

ax=0+2×x(2)+(x+y)×(2)y+(xyz)×(2)z 

ax = 0

ay=0+2×(x+y)x+(x+y)×(x+y)y+(xyz)×(x+y)z 

ay = 2 + x + y

az=0+2×(xyz)x+(x+y)×(xyz)y+xyz×(xyz)z 

= 0 + 2yz + (x + y) × (xz) + xyz × xy

az = 2yz + (x + y) × (xz) + x2y2z

Acceleration = axi + ayj + azk

a=0+(2+x+y)j+(2yz+(x+y)xz+x2y2z)k

a(1,1,2)=0+(2+1+1)j+(2×1×2+(1+1)×1×2+12×12×2)k

a=4j+(4+4+2)k=4j+10k
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