The temperature coefficient of resistance of a material is given as :

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  1. \(\frac{R_0-R_t}{R_t(t_1-t_2)}\)
  2. \(\frac{R_t}{R_0(t_2-t_1)}\)
  3. \(\frac{R_t-R_0}{R_0(t_2+t_1)}\)
  4. \(\frac{R_t-R_0}{R_0(t_2-t_1)}\)

Answer (Detailed Solution Below)

Option 4 : \(\frac{R_t-R_0}{R_0(t_2-t_1)}\)
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Detailed Solution

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Temperature coefficient of resistance

It is the calculation of a relative change of resistance per degree of temperature change.

The value of the resistance at temperature 't2' is given by:

\(R_t=R_o[1+α (t_2-t_1)]\)

where, Rt = Final resistance at temperature 't2'

Ro = Initial resistance at temperature 't1'

α = Temperature coefficient of resistance

The value of α is calculated as:

\({R_t\over R_o}=1+α (t_2-t_1)\)

\({R_t\over R_o}-1=α (t_2-t_1)\)

\({R_t-R_o\over R_o}=α (t_2-t_1)\)

\(α ={R_t-R_o\over R_o(t_2-t_1)}\)

Hence, the correct answer is option 4.

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