The soil has a bulk density of \(44\text{kN}/m^3\) and water content 10%. The dry density of soil is

This question was previously asked in
JKSSB JE (Civil) Official Paper (Held On: 19 Nov, 2023)
View all JKSSB JE Papers >
  1. \(4.4\text{kN}/m^3\)
  2. \(10\text{kN}/m^3\)
  3. \(20\text{kN}/m^3\)
  4. \(40\text{kN}/m^3\)

Answer (Detailed Solution Below)

Option 4 : \(40\text{kN}/m^3\)
Free
JKSSB JE Civil RCC Structures Mock Test
1.2 K Users
20 Questions 20 Marks 20 Mins

Detailed Solution

Download Solution PDF

Concept:

Dry density of soil is given by: \(\gamma_d=\frac{\gamma}{1+w} \)

where \(\gamma_d\) is dry density of soil; \(\gamma\) is bulk density of soil and w is water content of same soil.

Calculation:

Given: \(\gamma = 44kN/m^3; w=10%\)

So, dry density of soil is \(\gamma_d=\frac{44}{1+0.1}=40kN/m^3\)

Latest JKSSB JE Updates

Last updated on Jul 1, 2025

-> JKSSB Junior Engineer recruitment exam date 2025 for Civil and Electrical Engineering has been rescheduled on its official website. 

-> JKSSB JE exam will be conducted on 31st August (Civil), and on 24th August 2025 (Electrical).

-> JKSSB JE application form correction facility has been started. Candidates can make corrections in the JKSSB recruitment 2025 form from June 23 to 27. 

-> JKSSB JE recruitment 2025 notification has been released for Civil Engineering. 

-> A total of 508 vacancies has been announced for JKSSB JE Civil Engineering recruitment 2025. 

-> JKSSB JE Online Application form will be activated from 18th May 2025 to 16th June 2025 

-> Candidates who are preparing for the exam can access the JKSSB JE syllabus PDF from official website of JKSSB.

-> The candidates can check the JKSSB JE Previous Year Papers to understand the difficulty level of the exam.

-> Candidates also attempt the JKSSB JE Mock Test which gives you an experience of the actual exam.

Get Free Access Now
Hot Links: teen patti gold real cash teen patti - 3patti cards game all teen patti master teen patti real cash game teen patti baaz