The power and energy of the unit step sequence are respectively,

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ESE Electronics Prelims 2021 Official Paper
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  1. 1/2 and 0
  2. 1/2 and infinity
  3. 2 and 0
  4. 2 and infinity

Answer (Detailed Solution Below)

Option 2 : 1/2 and infinity
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The unit step signal is defined as,

 \( \begin{equation*} u(t)=\begin{cases} 1\quad &\text{if} \space \, t \geq{0} \\ 0 \quad &\text{if}\space \, t \leq {0} \\ \end{cases} \end{equation*} \)

The power of a signal is given as →

  \(P= \lim_{T \to ∞} \frac{1}{2T} \int\limits_{-T}^T x(t)^2dt \)

\(P= \lim_{T \to ∞} \frac{1}{2T} \int\limits_{-T}^0 0~dt \space + \lim_{T \to ∞} \frac{1}{2T} \int\limits_{0}^T 1~dt\)

\(P=\lim_{T \to ∞} \frac{1}{2T} \times T\)

\(P=\frac{1}{2}\)

The energy of the signal can be defined as→

 \(E= \lim_{T \to ∞} \int\limits_{-T}^T x(t)^2dt \)
\(E= \lim_{T \to ∞} \int\limits_{-T}^0 0dt \space + \lim_{T \to ∞} \int\limits_{0}^T 1dt\)

E = ∞ 

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