The path travelled by the free water jet is _______. 

Explanation:

The throw of a liquid jet can be quite large. Such a jet may reach beyond the limit of the area of the classification zone.

The simplest treatment of a liquid jet is based on the assumption that the jet suffers no drag and does not disintegrate (divide into two parts).

For a jet at ground level, as shown in the figure below the motion in the horizontal direction is given in two ways

a) jet from ground level source                                      (

b) jet from elevated source                       

Velocity in the x direction:

Where;

 t = time, u = horizontal velocity, x = horizontal distance, α = angle between jet and horizontal

Integrating the above equation,      

∴ x = utcosα

For motion in the vertical direction, we know that acceleration is only due to gravitation i.e. (g)

• Velocity along the vertical direction (uy) = usinα
• acceleration (a) = - g (acceleration due to gravity)
• distance (s) = y

From,

Substituting all the values in the above equation we get,

By comparing the above equation with the equation of parabola which is

y = Ax2 + Bx + c

We can say that the liquid jet from the nozzle will follow the parabolic path.