Question
Download Solution PDFThe output Y of the logic circuit given below is:-
This question was previously asked in
UJVNL AE EE 2016 Official Paper
Answer (Detailed Solution Below)
Option 1 : 1
Free Tests
View all Free tests >
ST 1: UJVNL AE EE - Electrical Circuits
1.5 K Users
20 Questions
20 Marks
20 Mins
Detailed Solution
Download Solution PDFXOR GATE
Symbol:
Truth Table:
Input A |
Input B |
Output Y = A ⊕ B |
0 |
0 |
0 |
0 |
1 |
1 |
1 |
0 |
1 |
1 |
1 |
0 |
Output Equation:
Key Points:
1) If B is always High, the output is the inverted value of the other input A, i.e. A̅.
1) The output is low when both the inputs are the same.
2) The output is high when both the inputs are different.
Explanation:
Y = 1
Name |
AND Form |
OR Form |
Identity law |
1.A=A |
0+A=A |
Null Law |
0.A=0 |
1+A=1 |
Idempotent Law |
A.A=A |
A+A=A |
Inverse Law |
AA’=0 |
A+A’=1 |
Commutative Law |
AB=BA |
A+B=B+A |
Associative Law |
(AB)C |
(A+B)+C = A+(B+C) |
Distributive Law |
A+BC=(A+B)(A+C) |
A(B+C)=AB+AC |
Absorption Law |
A(A+B)=A |
A+AB=A |
De Morgan’s Law |
(AB)’=A’+B’ |
(A+B)’=A’B’ |
Last updated on Apr 11, 2023
Uttarakhand Jal Vidyut Nigam Limited will soon release the official notification for an Assistant Engineer. With the detailed notification, the vacancy details will be released. According to the previous notification, a total of 21 vacancies for UJVNL AE Recruitment were released. To be eligible for the recruitment, applicants must meet the UJVNL AE Eligibility Criteria. The candidates are selected based on a written test and an interview.