The one root of equation 𝐏2−𝟏𝟎𝐏 + πŸπŸ“ = 𝟎 is x and [x/πŸ“ = 𝟏𝟏/ [𝒛 +𝟏].

Quantity I. 10z

Quantity II. 100

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  1. Quantity I < Quantity II

  2. Quantity I > Quantity II
  3. Quantity I ≥ Quantity II
  4. Quantity I ≤ Quantity II
  5. Quantity I = Quantity II or no relation

Answer (Detailed Solution Below)

Option 5 : Quantity I = Quantity II or no relation
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Calculation

P− 10P + 25 = 0

⇒ (P−5)2 =0

⇒ P = 5

So, both roots are 5

⇒ x = 5

Now,

[x/5] = [11/ z+1]

⇒ 5/5 = 11/[z+1]

⇒ 1 = 11z + 1 ⇒ z + 1 =11

⇒ z = 10

Quantity I: 10z = 10 × 10 = 100

Quantity II: 100

Both quantities are equal.
Quantity I = Quantity II

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