Question
Download Solution PDFf(x) ఒక విలోమనీయ ప్రమేయం అయితే, f(x) = \(\rm\frac{3x−2}{5}\) అయితే f−1(x) విలువ ఎంత?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFఉపయోగించిన భావన:
ఏదైనా ప్రమేయం f(x) కు, g(f(x) = x అయితే, g అనేది f(x) యొక్క విలోమం అంటారు.
గణన:
f(x) = \(\rm\frac{3x−2}{5}\)
f(x) = y అనుకుందాం
⇒ y = \(\rm\frac{3x−2}{5}\)
⇒ 5y = 3x - 2
⇒ x = \(\frac{5y + 2 }{3}\)
కాబట్టి, f-1(x) = \(\mathbf{\frac{5x + 2 }{3}}\).
Last updated on Jan 10, 2025
-> The OSSTET Result has been released.
-> The Odisha Secondary School Teachers Eligibility Test was held on 17th January 2025.
-> Candidates who have completed graduation and a degree in Education can appear for this exam.
-> Those who qualify the OSSTET can apply for the post of Secondary School Teacher in Odisha.
-> Candidates can check the OSSTET Previous Year Papers which help them to get the difficulty level of the exam. Also, attempt the OSSTET Test Series which helps you in preparation.