Probability of 3 students solving a question are \({1\over 2}, {1\over 3}, \) and \({1\over 4}\). Probability to solve the question is:

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BSSC Inter Level Pre PYP (5th Feb 2017)
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  1. \({1\over 4}\)
  2. \({1\over 2}\)
  3. \({7\over 12}\)
  4. \({3\over 4}\)

Answer (Detailed Solution Below)

Option 4 : \({3\over 4}\)
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Probability of 3 students,

P(A) = 1/2, P(A̅) = 1/2

P(B) = 1/3, P(B̅) = 2/3

P(C) = 1/4, P(C̅) = 3/4

So, Probability of no one solve the question is = \(\frac 1 2 \times \frac 2 3 \times \frac 3 4\) = 1/4

⇒ P(None) = 1/4

Then, The probability to solve the question is = 1 - 1/4 = 3/4

Hence, the correct answer is "3/4".

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