One of the two events, A and B must occur. If P (A) = (2/3) P (B), the odds in favour of B are

  1. 1 : 2
  2. 3 : 2
  3. 2 : 3
  4. 3 : 5

Answer (Detailed Solution Below)

Option 2 : 3 : 2
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Detailed Solution

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Concept:

Let an event A, Probability of occurring of A be P (A) and not occurring of A be P (Ac)

 

Calculation:

Given: One of the two events A and B must occur,

So: P (A) + P (B) = 1

⇒ (2/3) P (B) + P (B) = 1

∴ P (B) = 3/5

Now,

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