जर एखादी वस्तू 15 सेमी नाभीय अंतर असणाऱ्या बहिर्गोल भिंगापासून 30 सेमी अंतरावर ठेवली असेल, तर त्या बहिर्गोल भिंगाचे विशालन शोधा.

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Navik GD Physics 22 March 2021 (Shift 1+2) Questions
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  1. +1
  2. +0.5
  3. –0.5
  4. -1

Answer (Detailed Solution Below)

Option 4 : -1
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संकल्पना:

  • भिंगाचे सूत्र: वस्‍तूचे अंतर (u), प्रतिमेचे अंतर (v) आणि भिंगाचे नाभीय अंतर (f) यांचा परस्‍परसंबंध दाखविणारे सूत्र म्‍हणजे भिंगाचे सूत्र होय.

\(\frac{1}{v} - \frac{1}{u} = \frac{1}{f}\)

रेषीय विशालन (m):

  • प्रतिमेची उंची (hiआणि वस्तूची उंची  (ho) यांच्या गुणोत्तरास रेषीय विशालन म्हणतात.

म्हणून \(m = \frac{{{h_i}}}{{{h_o}}}\)

  • प्रतिमेचे अंतर आणि वस्तूचे अंतर यांच्या गुणोत्तराला रेषीय विशालन म्हणतात.

म्हणजेच \(m = \frac{{image\;distance\;\left( v \right)}}{{object\;distance\;\left( u \right)}} = \frac{v}{u}\)

गणना:

दिलेल्याप्रमाणे: u = - 30 सेमी आणि f = 15 सेमी

भिंगाचे सूत्र

\(\frac{1}{v} - \frac{1}{u} = \frac{1}{f}\)

\(\therefore \frac{1}{v} = \frac{1}{f} + \frac{1}{u} = \frac{1}{{15}} - \frac{1}{{30}} = \frac{{2 - 1}}{{30}} = \frac{1}{{30}}\;cm\)

v = 30 सेमी

रेषीय विशालन (m)

\(m = \frac{v}{u}\)

\(\Rightarrow m = \frac{{30}}{{ - 30}} = - 1\)

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