Question
Download Solution PDF∠A, ∠B आणि ∠C हे त्रिकोणाचे तीन कोन आहेत आणि /A / 4 + ∠B / 4 + ∠C / 5 = 41 °, तर ∠A + ∠B = चे मूल्य शोधा?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेले:
∠A, ∠B आणि ∠C हे त्रिकोणाचे तीन कोन आहेत.
∠A/4 + ∠B/4 + ∠C/5 = 41°
सूत्र:
त्रिकोणाच्या तीनही कोनांची बेरीज 180 ° आहे.
हिशोब:
∠A/4 + ∠B/4 + ∠C/5 = 41°
⇒ (5∠A + 5∠B + 4∠C)/20 = 41°
⇒ (∠A + 4∠A + ∠B + 4∠B + 4∠C)/20 = 41°
⇒ (∠A + ∠B + 4∠A + 4∠B + 4∠C)/20 = 41°
⇒ ∠A + ∠B + 4(∠A + ∠B + ∠C) = 41° × 20
⇒ ∠A + ∠B + 4 × 180° = 820°
⇒ ∠A + ∠B = 820° - 720°
⇒ ∠A + ∠B = 100°
Last updated on Jun 26, 2025
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