Question
Download Solution PDFIron is 9 times as heavy as Copper and Zinc is 23 times as heavy as Copper. What should be the ratio of Iron and Zinc in the new mixture to get a mixture which must be 13 times as heavy as Copper?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Iron = 9 × Copper
Zinc = 23 × Copper
Calculation:
Let the weight of copper is an x kg/unit
Then the weight of Iron = 9x
Weight of Zinc = 23x
Weight of mixture = 13x
Then, the required ratio is 5 : 2.
∴ The ratio of Iron and Zinc in the new mixture is 5 : 2.
Last updated on Jun 17, 2025
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