Question
Download Solution PDFIn the case of small BJT model with the common emitter, the collector current ic is 1.3 mA, when the collector-emitter voltage is Vce of 2.6 V. The output conductance of the circuit is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The conductance of an amplifier is defined as the ratio of the collector current to the collector to emitter voltage of the BJT, i.e.
IC = Collector current
Vce = Collector to emitter voltage
Calculation:
With Vce = 2.6 V and Ic = 1.3 mA, the conductance will be:
g0 = 0.5 m℧, where ℧ is the inverse of resistance (Ω).
Last updated on Jul 2, 2025
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