In a mixture the ratio of liquid A and liquid B is 3 ∶ 2. If a 5-liter mixture is drawn out and in the final mixture, the quantity of liquid A is 12 litre more than liquid B, then find the initial quantity of liquid A in the mixture.

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  1. 36 litre
  2. 39 litre
  3. 32 litre
  4. 45 litre
  5. 42 litre

Answer (Detailed Solution Below)

Option 2 : 39 litre
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Detailed Solution

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Given

Quantity of A: Quantity of B = 3: 2

Calculation

Let the initial quantity of A and B be 3x and 2x.

A total of 5 lt of the mixture is drawn out.

Hence, quantity of A drown out = 5 × (3/5) = 3 lt

And, quantity of B drown out = 5 × (2/5) = 2 lt

According to question

(3x - 3) - (2x - 2) = 12

⇒ x - 1 = 12

⇒ x = 13

∴ Initial quantity of A = 3x = 3 × 13 = 39 litres.

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