Question
Download Solution PDFIn a common base connection, if the emitter current is 2 mA and collector current is 1.95 mA, then the base current will be:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
1.) Common emitter current gain (β)
\(\beta={I_C\over I_B}\)
2.) Common base current gain (α)
\(\alpha={I_C\over I_E}\)
3.) Common collector current gain (γ)
\(\beta={I_E\over I_B}\)
Also, \(I_E=I_C+I_B\)
where, IC = Collector current
IB = Base Current
IE = Emitter current
Calculation
Given, IE = 2 mA
IC = 1.95 mA
\(2=1.95+I_B\)
IB = 0.05 mA
Last updated on May 29, 2025
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