Question
Download Solution PDFIn a common base configuration, the alpha of the transistor is 0.99, its collector current is 1 mA and the collector to base current with emitter open is 1 μA. The value of base current is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
In a common base connection,
IE = IB + IC
And IC = α IE + ICBO
Where α is the current amplification factor
Calculation:
Given that,
α = .99
ICBO = 1 μA
IC = 1 mA
⇒
⇒
⇒ IB ≈ 9 μA
Last updated on Jul 2, 2025
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