Question
Download Solution PDFIf the points (k, 2k); (3k, 3k) and (3, 1) are collinear, then the value of k is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
If the point A = (x1, y1), B = (x2, y2) and C = (x3, y3) are collinear then , then the area of triangle ABC is zero.
The area of triangle ABC with vertices A = (x1, y1), B = (x2, y2) and C = (x3, y3) is given by,
Area =
Calculations:
Given points A = (k, 2k) = (x1, y1), B = (3k, 3k) = (x2, y2) and C = (3, 1) = (x3, y3) are collinear
If the point A = (x1, y1), B = (x2, y2) and C = (x3, y3) are collinear then , then the area of triangle ABC is zero.
The area of triangle ABC with vertices A = (x1, y1), B = (x2, y2) and C = (x3, y3) is given by,
Area =
⇒ 0 =
⇒ 0 =
⇒ 0 =
⇒ k =
Hence, the points (k, 2k); (3k, 3k) and (3, 1) are collinear, then the vale of k is =
Last updated on Jul 4, 2025
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