If  and det (A3) = 125, then α is equal to

This question was previously asked in
NDA (Held On: 23 April 2017) Maths Previous Year paper
View all NDA Papers >
  1. ± 1
  2. ± 2
  3. ± 3
  4. ± 5

Answer (Detailed Solution Below)

Option 3 : ± 3
Free
UPSC NDA 01/2025 General Ability Full (GAT) Full Mock Test
150 Qs. 600 Marks 150 Mins

Detailed Solution

Download Solution PDF

Concept:

1. If  then determinant of A is given by: |A| = a11 × a22 – a21 × a12

2. |An| = |A|n

Calculation:

Given that,

 and det{A3} = 125

⇒ |A| = α × α – 2 × 2

⇒ |A| = α2 - 4     ...1)

Given |A3| = 125

⇒ |A|3 = 125     ...[∵ |An| = |A|n]

⇒ |A| = (125)1/3 = 5     ...2)

From equations 1 and 2

⇒ α2 - 4 = 5

⇒ α2 = 9

⇒ α = ± 3

Latest NDA Updates

Last updated on Jul 8, 2025

->UPSC NDA Application Correction Window is open from 7th July to 9th July 2025.

->UPSC had extended the UPSC NDA 2 Registration Date till 20th June 2025.

-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.

->The NDA exam date 2025 has been announced. The written examination will be held on 14th September 2025.

-> The selection process for the NDA exam includes a Written Exam and SSB Interview.

-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100. 

-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential. 

More Evaluation of Determinants Questions

More Determinants Questions

Hot Links: teen patti list teen patti rummy 51 bonus teen patti neta