If an amplitude modulated wave 10[1 + 0.6 cos 2π103t] cos2π.106 .t is to be detected by a linear diode detector, then the time constant will be: 

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UGC NET Paper 2: Electronic Science 3rd Dec 2021 Shift 2
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  1. 0.21 msec
  2. 0.17 msec
  3. 17 msec
  4. 0.17 sec 

Answer (Detailed Solution Below)

Option 1 : 0.21 msec
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UGC NET Paper 1: Held on 21st August 2024 Shift 1
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Detailed Solution

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Concept:

For envelope detector, the time constant must satisfy the following relation:

\(RC \le \frac{1}{{{\omega _m}}}\left[ {\frac{{\sqrt {1 - {μ^2}} }}{μ}\;} \right]\)  ---(1)

For the good performance of the envelope detector:

\(\frac{1}{\omega_c}<<RC<<\frac{1}{\omega_m}\)

Application:

Given:

\(\omega_m\) =  2π103  rad/sec

modulation index (μ) = 0.6

From (1), we get

\(RC \le \frac{1}{{{2\pi \times 10^3}}}\left[ {\frac{{\sqrt {1 - {0.6^2}} }}{0.6}\;} \right]\)

        =0.21 msec

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