1002 - 992 + 982 - 972 + 962 - 952 + 942 - 932 + ................ 12 2- 11का मान ज्ञात कीजिए।

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SSC CGL 2022 Tier-I Official Paper (Held On : 05 Dec 2022 Shift 3)
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  1. 5050
  2. 4985
  3. 4995
  4. 4950

Answer (Detailed Solution Below)

Option 3 : 4995
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दिया गया है:

1002 - 992 + 982 - 972 + 962 - 952 + 942 - 932 + ................ 12 2- 112

प्रयुक्त अवधारणा:

हम जानते हैं, क्रमिक पद की कुछ n संख्या = n(n + 1)/2

गणना:

1002 - 992 + 982 - 972 + 962 - 952 + 942 - 932 + ...... + 122 - 112

⇒ (1002 - 992) + (982 - 972) + (962 - 952) + (942 - 932) + ...... + (122 - 112)

⇒ (100 - 99)(100 + 99) + (98 - 97)(98 + 97) + (96 - 95)(96 + 95) + (94 - 93)(94 + 93) + ...... + (12 - 11)(12 + 11)

⇒ 1(100 + 99) + 1(98 + 97) + 1(96 + 95) + 1(94 + 93) + ...... + 1(12 + 11)

⇒ 100 + 99 + 98 + 97 + 96 + 95 + 94 + 93 + ...... + 12 + 11

अब,

[100(100 + 1)]/2 - [10(10 + 1)]/2

⇒ 50 × 101 - 5 × 11

⇒ 5050 - 55

⇒ 4995

∴ अभीष्ट उत्तर 4995 है।

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