Question
Download Solution PDFधारा 2A की एक अर्ध तरंग दिष्टकारी सममित वर्गाकार तरंग का r.m.s. मान क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFअर्ध तरंग दिष्टकारी:
एक प्रकार की परिपथ व्यवस्था जो केवल AC वोल्टेज तरंगरुप के एक अर्ध चक्र को पारित करने की अनुमति देती है अन्य आधे अर्ध चक्र का अवरुद्ध करती है।
वर्ग तरंग इनपुट के लिए, आउटपुट इस प्रकार होगा
RMS वोल्टेज के लिए सूत्र:
\(I_{rms}^2 = \frac{1}{T}\mathop \smallint \limits_0^T {I^2}\left( t \right)\;dt\)
जहाँ Vrms = धारा का RMS मान
T = समयावधि
V(t) = धारा
गणना:
दिया गया है:
T = 2π
V(t) = 2 A
\(I_{rms}^2 = \frac{1}{{2\pi }}\mathop \smallint \limits_0^{2\pi } {I^2}\left( t \right)dt = \frac{1}{{2\pi }}\left[ {\mathop \smallint \limits_0^\pi {I^2}\left( t \right)dt + \mathop \smallint \limits_\pi ^{2\pi } 0dt} \right]\)
\(I_{rms}^2 = \frac{1}{{2\pi }}\mathop \smallint \limits_0^\pi {2^2}dt\)
\(I_{rms}^2 = \frac{1}{{2\pi }}4\pi = 2\)
Irms = √2 A
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