Question
Download Solution PDF45° के कोण पर झुके हुए दो दर्पणों के बीच रखी गई वस्तु की छवियों की संख्या क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFअवधारणा:
समतल दर्पण
- एक समतल दर्पण एक सपाट (समतलीय) परावर्तक सतह वाला एक दर्पण है।
वस्तु को दो समतल दर्पणों के बीच रखे जाने पर निर्मित बिम्बों की संख्या:
⇒ θ = दो समतल दर्पण के बीच कोण, और n = निर्मित बिम्बों की संख्या
- If = सम संख्या
- If = विषम संख्या और वस्तु सममित है
- If = विषम संख्या और वस्तु असममित है
- If = अंश
⇒ n = का पूर्णांक भाग
गणना:
दिया गया है कि:
θ = 45°
\({\rm{Number\;of\;images}} = \frac{{360}}{θ } - 1\)
छवियों की संख्या (n) = (360/45) - 1 = 8 - 1 = 7
तो विकल्प 3 सही है।
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