Question
Download Solution PDFवक्र y = a sin (λx + α) की श्रेणी को दर्शाने वाला अवकल समीकरण क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
\(\rm \frac{d\sin x}{dx} = \cos x\\ \rm \frac{d\cos x}{dx} = -\sin x\)
गणना:
दिया गया है:
y = a sin (λx + α) .... (1)
अब दोनों पक्षों का अवकलन करने पर, हमें निम्न प्राप्त होता है
\(⇒ \rm \frac{dy}{dx} = \frac{a d\sin{(\lambda x + \alpha)}}{d(\lambda x + \alpha)}\times\frac{{d(\lambda x + \alpha)}}{dx} \)
⇒ \(\rm \frac{dy}{dx} = a\lambda\cos\;(\lambda x+\alpha)\)
फिर से दोनों पक्षों का अवकलन करने पर, हमें निम्न प्राप्त होता है
\(\Rightarrow \frac{{{{\rm{d}}^2}{\rm{y}}}}{{{\rm{d}}{{\rm{x}}^2}}} = \rm -a\lambda^2\) sin (λx + α)
समीकरण 1 से,
\(\Rightarrow \frac{{{{\rm{d}}^2}{\rm{y}}}}{{{\rm{d}}{{\rm{x}}^2}}} = \rm -\lambda^2 y\)
∴ \(\rm \frac {d^2y}{dx^2} + \lambda^2y = 0\)
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