Question
Download Solution PDFअतिपरवलय
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
एक अतिपरवलय का मानक समीकरण:
- फोकस के निर्देशांक = (± ae, 0)
- उत्केंद्रता (e) =
⇔ a2e2 = a2 + b2 - नाभिलंब की लम्बाई =
गणना:
दिया गया है:
अतिपरवलय के मानक समीकरण के साथ तुलना करने पर:
इसलिए, a2 = 16 और b2 = 9
⇒ a = 4 और b = 3 (a > b)
अब, उत्केंद्रता (e) =
=
=
=
फोकस के निर्देशांक = (± ae, 0)
= (± 5, 0)
Last updated on Jun 30, 2025
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