Question
Download Solution PDFत्रिभुज ABC में, कोण BAC का समद्विभाजक रेखा BC को D पर काटता है। यदि BD = 6 और BC = 14 है, तो AB ∶ AC का मान क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
त्रिभुज ABC में कोण BAC का समद्विभाजक रेखा BC को D पर काटता है।
BD = 6 और BC = 14
प्रयुक्त अवधारणा:
कोण द्विभाजक प्रमेय: एक त्रिभुज का कोण द्विभाजक विपरीत भुजा को त्रिभुज की अन्य दो भुजाओं के समानुपाती दो भागों में विभाजित करता है।
गणना:
DC = BC - BD = 14 - 6 = 8 सेमी
कोण द्विभाजक प्रमेय के अनुसार,
BD/CD = AB/AC
⇒ 6/8 = AB/AC
⇒ AB : AC = 3 : 4
∴ AB : AC का मान 3 : 4 है।
Last updated on Jul 9, 2025
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