यदि रैखिक समीकरणों का निकाय

2x + 2y + 3z = a

3x - y + 5z = b

x - 3y + 2z = c

जहाँ a, b, c शून्येतर वास्तविक संख्याएँ हैं, के एक से अधिक हल हैं, तो:

 

This question was previously asked in
JEE Mains Previous Paper 1 (Held On: 11 Jan 2019 Shift 1)
View all JEE Main Papers >

Answer (Detailed Solution Below)

Option 2 :
Free
JEE Main 04 April 2024 Shift 1
90 Qs. 300 Marks 180 Mins

Detailed Solution

Download Solution PDF

यदि समीकरणों के निकाय के एक से अधिक हल हैं, तो D = 0 और D1 = D2 = D3 = 0 है। 

दिए गए समीकरणों के समुच्चय से, हम बनाते हैं,

D1 = 0

अब,

 

 

Latest JEE Main Updates

Last updated on May 23, 2025

-> JEE Main 2025 results for Paper-2 (B.Arch./ B.Planning) were made public on May 23, 2025.

-> Keep a printout of JEE Main Application Form 2025 handy for future use to check the result and document verification for admission.

-> JEE Main is a national-level engineering entrance examination conducted for 10+2 students seeking courses B.Tech, B.E, and B. Arch/B. Planning courses. 

-> JEE Mains marks are used to get into IITs, NITs, CFTIs, and other engineering institutions.

-> All the candidates can check the JEE Main Previous Year Question Papers, to score well in the JEE Main Exam 2025. 

More Linear Inequations Questions

Hot Links: all teen patti teen patti gold download teen patti earning app teen patti glory teen patti baaz