Question
Download Solution PDFयदि रैखिक समीकरणों का निकाय
2x + 2y + 3z = a
3x - y + 5z = b
x - 3y + 2z = c
जहाँ a, b, c शून्येतर वास्तविक संख्याएँ हैं, के एक से अधिक हल हैं, तो:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFयदि समीकरणों के निकाय के एक से अधिक हल हैं, तो D = 0 और D1 = D2 = D3 = 0 है।
दिए गए समीकरणों के समुच्चय से, हम बनाते हैं,
D1 = 0
अब,
Last updated on May 23, 2025
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