यदि P(A) = 0.4, P(B) = 0.8 और P(B|A) = 0.6 तो P(A ∪ B) किसके बराबर है?

  1. 0.24
  2. 0.3
  3. 0.48
  4. 0.96

Answer (Detailed Solution Below)

Option 4 : 0.96
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संकल्पना:

दो घटनाओं A और B के लिए:

  • P(A ∪ B) = P(A) + P(B) - P(A ∩ B)
  • B दी गई A की सप्रतिबन्ध प्रायिकता को इस प्रकार परिभाषित किया गया है:  P(B|A) = \(\rm \dfrac{P(A\cap B)}{P(A)}\) , जब P(A)> 0

 

गणना:

P(B|A) = \(\rm \dfrac{P(A\cap B)}{P(A)}\) हम प्राप्त करते हैं:

0.6 = \(\rm \dfrac{P(A\cap B)}{0.4}\)

⇒ P(A ∩ B) = 0.24

अब P(A ∪ B) = P(A) + P(B) - P(A ∩ B) के संबंध का उपयोग करते हुए, हम पाते हैं:

P(A ∪ B) = 0.4 + 0.8 - 0.24 = 0.96

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