यदि a + b + c = 5, a3 + b3 + c3 = 85 और abc = 25 है, तो a2 + b2+ c2 - ab - bc - ca का मान ज्ञात कीजिए।

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SSC CGL 2022 Tier-I Official Paper (Held On : 13 Dec 2022 Shift 4)
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Answer (Detailed Solution Below)

Option 1 : 2
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दिया गया है:

a + b + c = 5

a+ b3 + c3 = 85

a × b × c = 25

प्रयुक्त सूत्र:

a3 + b3 + c3 - 3 × a × b × c = (a + b + c)(a2 + b2+ c2 - ab - bc - ca)

गणना:

(a + b + c)(a2 + b2+ c2 - ab - bc - ca) = a3 + b3 + c3 - 3 × a × b × c

⇒ 5 × (a2 + b2+ c2 - ab - bc - ca) = 85 - (3 × 25)

⇒ (a2 + b2+ c2 - ab - bc - ca) = 10/5 = 2

∴ सही उत्तर 2 है।

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