केंद्र ( 3, 2) और त्रिज्या 7 इकाई वाले वृत्त का समीकरण ज्ञात कीजिए। 

  1. x2+ y2- 6x- 4y+ 36 = 0
  2. x2+ y2- 6x- 4y- 36 = 0
  3. x2+ y2+6x- 4y- 36 = 0
  4. x2+ y2+ 6x+ 4y+ 36 = 0

Answer (Detailed Solution Below)

Option 2 : x2+ y2- 6x- 4y- 36 = 0
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Detailed Solution

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संकल्पना:

केंद्र (h, k) और त्रिज्या r वाले वृत्त का समीकरण निम्न है

 (x – h) 2 + (y – k) 2 = r 

गणना:

दिया गया है, वृत्त का केंद्र ( 3, 2) और त्रिज्या 7 इकाई है।

हम जानते हैं कि, वृत्त का समीकरण (x – h) 2 + (y – k) 2 = rहै। 

( x - 3 )2 + ( y - 2 )2 = 72 

⇒ x2+ 9 - 6x + y2+ 4 - 4y = 49 

x2 + y2- 6x - 4y - 36 = 0

 सही विकल्प 2 है। 

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