Question
Download Solution PDFसमानांतर रेखा 3y + 4x - 12 = 0 और 3y + 4x - 7 = 0 के बीच की दूरी ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
समानांतर रेखा ax + by + c1 और ax + by + c2 के बीच की दूरी को निम्न द्वारा ज्ञात किया गया है:
D =
गणना:
दी गयी 2 रेखाएं निम्न हैं:
3y + 4x - 12 = 0
3y + 4x - 7 = 0
a = 4, b = 3, c1 = -12 और c2 = -7
∴ रेखाओं के बीच की दूरी
D =
⇒ D =
⇒ D =
Last updated on Jul 7, 2025
->UPSC NDA Application Correction Window is open from 7th July to 9th July 2025.
->UPSC had extended the UPSC NDA 2 Registration Date till 20th June 2025.
-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.
->The NDA exam date 2025 has been announced. The written examination will be held on 14th September 2025.
-> The selection process for the NDA exam includes a Written Exam and SSB Interview.
-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100.
-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential.