रेखा r=(i^+2j^k^)+λ(i^j^+k^) और तल r(2i^j^+k^)=6 के बीच का कोण ज्ञात कीजिए। 

  1. sin1(223)
  2. sin1(23)
  3. sin1(23)
  4. इनमें से कोई नहीं 

Answer (Detailed Solution Below)

Option 1 : sin1(223)
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संकल्पना:

यदि θ रेखा r=a+λb और तल rn=q के बीच का कोण है, तो निम्न दिया गया है: sinθ=bn|b|×|n|

गणना:

दिया गया है: रेखा का समीकरण r=(i^+2j^k^)+λ(i^j^+k^) और तल का समीकरण r(2i^j^+k^)=6

यहाँ, हमें दी गयी रेखा और तल के बीच का कोण ज्ञात करना है। 

चूँकि हम जानते हैं कि, यदि θ रेखा r=a+λb और तल rn=q के बीच का कोण है, तो निम्न दिया गया है: sinθ=bn|b|×|n|

यहाँ, b=i^j^+k^ और n=2i^j^+k^

⇒ bn=2+1+1=4|b|=12+(1)2+12=3and|n|=22+(1)2+(1)2=6

 sinθ=bn|b|×|n| में उपरोक्त दिए गए मानों को रखने पर, हमें निम्न प्राप्त होता है

sinθ=43×6=223

θ=sin1(223)

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