नीचे दिखाए गए परिपथ में V(t) = 20 sin (50t + 10) V के लिए धारा की गणना करें।

F1 Engineering Priya 18 10 24  D9

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  1. I(t)= 2.27 sin (50t + 10°) m A
  2. I(t)= 3.41 sin (50t + 10°) m A
  3. I(t)= 1.14 sin (50t + 10°) m A
  4. I(t)= 4.55 sin (50t + 10°) m A

Answer (Detailed Solution Below)

Option 4 : I(t)= 4.55 sin (50t + 10°) m A
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संप्रत्यय

किसी भी परिपथ में धारा निम्न द्वारा दी जाती है:

I(t)=V(t)R

जहाँ, I(t) = धारा

V(t) = वोल्टेज

R = प्रतिरोध

गणना

दिया गया है, V(t) = 20 sin (50t + 10°) V

R = 4.4 kΩ

I(t)=20sin(50t+10)4.4

I(t)= 4.55 sin (50t + 10°) mA

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