For the Bode plot of the system

 the corner frequencies are:

This question was previously asked in
ESE Electronics 2011 Paper 2: Official Paper
View all UPSC IES Papers >
  1. 0.66 and 0.33
  2. 0.22 and 2.00
  3. 0.30 and 2.33
  4. 0.50 and 3.00

Answer (Detailed Solution Below)

Option 4 : 0.50 and 3.00
Free
ST 1: UPSC ESE (IES) Civil - Building Materials
20 Qs. 40 Marks 24 Mins

Detailed Solution

Download Solution PDF

Concept:

Corner frequency:

The point in Bode plot, where slope changes i.e. location of poles & zeros.

Calculation:

 

 

From above open loop transfer function we get,

Poles = - 0.5, - 3.03

No of corner frequencies = 2

Given system have corner frequency = 0.5, 3.03

Note:

In general, bode plot will have transfer function in time constant form.

i.e.

 

where, std. the open-loop transfer function for bode plot;

 

By comparing;

K = 6.6

 &  are corner frequencies.

Latest UPSC IES Updates

Last updated on Jul 2, 2025

-> ESE Mains 2025 exam date has been released. As per the schedule, UPSC IES Mains exam 2025 will be conducted on August 10. 

-> UPSC ESE result 2025 has been released. Candidates can download the ESE prelims result PDF from here.

->  UPSC ESE admit card 2025 for the prelims exam has been released. 

-> The UPSC IES Prelims 2025 will be held on 8th June 2025.

-> The selection process includes a Prelims and a Mains Examination, followed by a Personality Test/Interview.

-> Candidates should attempt the UPSC IES mock tests to increase their efficiency. The UPSC IES previous year papers can be downloaded here.

More Frequency Response Analysis Questions

Hot Links: teen patti royal - 3 patti lotus teen patti teen patti win teen patti master official online teen patti