For a 1-phase full-bridge inverter fed from 48 V dc and connected to load resistance of 2.4 Ω, the rms value of fundamental component of output voltage is

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ESE Electrical 2015 Paper 2: Official Paper

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Answer 1

Concept:

The output voltage of a single-phase inverter is given by,

\({V_0}\left( {rms} \right) = \frac{{4{V_s}}}{{n\pi }} \times \frac{1}{{\sqrt 2 }}\)

Fundamental component of output voltage is \({V_{01}} = \frac{{4{V_s}}}{\pi } \times \frac{1}{{\sqrt 2 }}\)

Calculation:

Given that, input dc voltage (V_S) = 48 V

Fundamental component of output voltage is \({V_{01}} = \frac{{4 \times 48}}{\pi } \times \frac{1}{{\sqrt 2 }} = 43.2\;V\)